(2z^2)+z-2=3z-7

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Solution for (2z^2)+z-2=3z-7 equation: 



(2z^2)+z-2=3z-7

We move all terms to the left:

(2z^2)+z-2-(3z-7)=0

We get rid of parentheses

2z^2+z-3z+7-2=0

We add all the numbers together, and all the variables

2z^2-2z+5=0

a = 2; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·2·5
Δ = -36
Delta is less than zero, so there is no solution for the equation

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